Answer:
[tex]= \mathbf{C_3H_6O}[/tex]
Explanation:
From the given information, since the molecular mass of the ion M+ is not given;
Let's assume M+ = 58.0423
So, by applying the 13th rule;
we will need to divide the mass by 13, after dividing it;
The quotient n = no. of carbon; &
The addition of the quotient (n) with the remainder r = no. of hydrogen.
So;
[tex]\dfrac{58}{13}= 4 \ remainder \ 6[/tex]
So;
[tex]C_nH_{n+r} = C_4H_{4+6}[/tex]
[tex]= C_4H_{10}[/tex]
From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing [tex]CH_4[/tex]. Also, since the mass is an even number then Nitrogen is 0.
So, we have:
[tex]= \mathbf{C_3H_6O}[/tex]
