Answer:
[tex]n_{P_2O_5}^{max}=1.4molP_2O_5[/tex]
Explanation:
Hello!
In this case, since the reaction between phosphorous and oxygen to form diphosphorous pentoxide is:
[tex]2P+\frac{5}{2}O_2\rightarrow P_2O_5[/tex]
Thus, since phosphorous is in excess and oxygen and diphosphorous pentoxide are in a 5/2:1 mole ratio, we can compute the maximum moles of product as shown below:
[tex]n_{P_2O_5}^{max}=112 gO_2*\frac{1molO_2}{32.00gO_2}*\frac{1molP_2O_5}{5/2molO_2}\\\\ n_{P_2O_5}^{max}=1.4molP_2O_5[/tex]
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