Solve 16x + 181 = 12x. Identify the solution and an extraneous solution.
A. Solution: x= -1; extraneous solution: x = 3
B. Solution: x = 1; extraneous solution: x = -3
C. Solution: x = 3; extraneous solution: x= -3
D. Solution: x= 3; extraneous solution: x = -1

The answer is 3
The question is wrong tho its not the same as the picture
Its not
16x + 181 = 12x
Its
6x +18= 12x
And the solution is
-18 on bothes sides then we have left 6x=12x-18
Then we take -12x on both sides
6x-12x= -18 6x-12x = -6x
-6x=-18

The u divede -18 = -6x
———
-6 -6
Then u get -18/-6= 3 and -6x/-6 = x
x = 3

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dfhlegendthe1 dfhlegendthe1 · Answer 2 · 2021-01-23T19:35:51+01:00

dfhlegendthe1 dfhlegendthe1

23-01-2021

Answer:

I think the answer is C. Solution: x = 3; extraneous solution: x= -3

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Solve 16x + 181 = 12x. Identify the solution and an extraneous solution. A. Solution: x= -1; extraneous solution: x = 3 B. Solution: x = 1; extraneous solution: x = -3 C. Solution: x = 3; extraneous solution: x= -3 D. Solution: x= 3; extraneous solution: x = -1

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Solve 16x + 181 = 12x. Identify the solution and an extraneous solution.
A. Solution: x= -1; extraneous solution: x = 3
B. Solution: x = 1; extraneous solution: x = -3
C. Solution: x = 3; extraneous solution: x= -3
D. Solution: x= 3; extraneous solution: x = -1