Answer:
48 and 88
Step-by-step explanation:
let the 2 numbers be x and y , then
x - y = 40 → (1)
[tex]\frac{y}{x}[/tex] = [tex]\frac{6}{11}[/tex] ( cross- multiply )
6x = 11y → (2)
From (1) x = 40 + y → (3)
Substitute x = 40 + y into (2)
6(40 + y) = 11y
240 + 6y = 11y ( subtract 6y from both sides )
240 = 5y ( divide both sides by 5 )
48 = y
Substitute y = 48 into (3)
x = 40 + 48 = 88
The 2 numbers are 48 and 88
