Answer:
Empirical formula = K₂SO₄
The name of the compound is Potassium tetraoxosulfate (vi)
Explanation:
Percentage composition of the elements:
Potassium = 44.82%
Sulfur = 18.39%
Oxygen = 36.79%
Mole ratio of the elements:
Potassium = 44.82/39 =1.15
Sulfur = 18.39/32 = 0.57
Oxygen = 36.79/16 = 2.29
Dividing by the smallest ratio in order to obtain the simplest ratio
Potassium = 1.15/0.57 =2
Sulfur = 0.57/0.57 = 1
Oxygen = 2.29/0.57 = 4
Therefore, the mole ratio of Potassium : Sulfur : Oxygen = 2:1:4
Empirical formula = K₂SO₄
The name of the compound is Potassium tetraoxosulfate (vi)
The empirical formula for the given compound has been [tex]\rm \bold{K_2SO_4}[/tex].
The empirical formula has been the simplest whole-number ratio of the atoms of each element present in the compound.
The atoms of K can be given by:
Atoms = [tex]\rm \dfrac{Percentage}{Molecular\;mass}[/tex]
The atoms of K = 1.15
The atoms of S = 0.57
The atoms of O = 2.29
To obtain the whole number ratio, the atoms have been divided by the smallest atom number i.e. 0.57.
The atoms of K = 2
The atoms of S = 1
The atoms of O = 4
Thus, the empirical formula for the given compound has been [tex]\rm \bold{K_2SO_4}[/tex].
For more information about the empirical formula, refer to the link:
https://brainly.com/question/11588623
