Answer: Well take this for an example and see if it helps with 50 grams of sucrose
Explanation:
Explanation:
And we have to calculate the number of moles of sucrose present in a
lb
mass of sucrose:
Moles of sucrose
=
454
⋅
g
342.30
⋅
g
⋅
m
o
l
−
1
=
1.33
⋅
m
o
l
.
Now it is a fact that in a
mole
of stuff there are
6.022
×
10
23
individual items of stuff.........
So
1.33
⋅
m
o
l
×
6.022
×
10
23
⋅
m
o
l
−
1
≅
8
×
10
23
individual
sucrose molecules
