Answer:
False.
General Formulas and Concepts:
Calculus
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Integration
- Integrals
- Definite Integrals
- Integration Constant C
Integration Rule [Fundamental Theorem of Calculus 2]: [tex]\displaystyle \frac{d}{dx}[\int\limits^x_a {f(t)} \, dt] = f(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle F(x) = \int\limits^{3x}_{-2} {sin(t)} \, dt[/tex]
Step 2: Differentiate
- Chain Rule: [tex]\displaystyle F'(x) = \frac{d}{dx}[\int\limits^{3x}_{-2} {sin(t)} \, dt] \cdot \frac{d}{dx}[3x][/tex]
- Rewrite [Derivative Property - Multiplied Constant]: [tex]\displaystyle F'(x) = \frac{d}{dx}[\int\limits^{3x}_{-2} {sin(t)} \, dt] \cdot 3\frac{d}{dx}[x][/tex]
- Basic Power Rule: [tex]\displaystyle F'(x) = \frac{d}{dx}[\int\limits^{3x}_{-2} {sin(t)} \, dt] \cdot 3x^{1 - 1}[/tex]
- Simplify: [tex]\displaystyle F'(x) = 3\frac{d}{dx}[\int\limits^{3x}_{-2} {sin(t)} \, dt][/tex]
- Integration Rule [Fundamental Theorem of Calculus 2]: [tex]\displaystyle F'(x) = 3sin(3x)[/tex]
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
