Answer:
1. 22
2. 12
3. Sorry, I'm unable to solve for 3.
4. 5
Step-by-step explanation:
AB is congruent to AD so let's solve the equation:
[tex] \: \: \: \: \: \: \: \: \: \: \: 8x - 2 = 6x + 4 \\ \frac{ - 6x \: \: \: \: \: \: \: \: \: \: \: = - 6x}{2x - 2 = 4} \\ \frac{ \: \: \: \: \: \: \: \: \: \: + 2 = + 2}{ \frac{2x}{2} = \frac{6}{2} } \\ x = 3[/tex]
☆Now we plug in for AD.
[tex]AD \\ 6x + 4 \\ 6(3) + 4 \\ 18 + 4 \\ 22[/tex]
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m<CED is on a right angle, that angle equal 90 degrees.
[tex]7x + 6 = 90 \\ \frac{ \: \: \: \: \: \: - 6 = - 6}{ \frac{7x}{7} = \frac{84}{7} } \\ x = 12[/tex]
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#4. You can do the Pythagorean theorem
[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {4}^{2} + {3}^{2} = {c}^{2} \\ {16} + 9 = {c}^{2} \\ \sqrt{25} = {c}^{2} \\ 5 = c[/tex]
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