The range of a function is the complete set of the all possible resulting values for that function. The range of the given function is 5/3.
The given function in the problem is,
[tex]f(x) = -3x^2 + 5[/tex]
The range of a function is the complete set of the all possible resulting values for that function.
Now the given function is,
[tex]f(x) = -3x^2 + 5[/tex]
Let [tex]f(x) [/tex] is equal to the y then,
[tex]\begin{aligned}\\ y&=-3x^2+5\\ 3x^2&=5-y\\ x&=\sqrt{\dfrac{5-y}{3} } \\ \end[/tex]
As the there is all the values where some x-value with y. Thus the range of the given function will be the domain which is,
[tex]\sqrt{\dfrac{5-y}{3} } [/tex]
Thus the domain of [tex]\sqrt{\dfrac{5-y}{3} } [/tex] is just all the values where,
[tex]{\dfrac{5-y}{3} }\leq 0[/tex]
Thus the range of the given function is 5/3.
Learn more about the range here;
https://brainly.com/question/8041076
