help please !! Given sin theta= 2/5
and 0°

Answer:
C
Step-by-step explanation:
sinθ=[tex]\frac{2}{5}[/tex]
θ=sin⁻¹ ( [tex]\frac{2}{5}[/tex] )
θ=23.57817848
2θ=47.15635696
sin2θ=sin(47.15635696)=0.7332121112°≈ ((4[tex]\sqrt{21}[/tex])/25)