Answer:
The displacement of the sound wave for Sound A + B at 0.1025 is;
D. 1.6162
Explanation:
The sum of the displacement of two sound waves is given by the principle of superposition as follows;
y(x, t) = [tex]y_m[/tex]·sin(k·x - ω·t) + [tex]y_m[/tex]·sin(k·x - ω·t + ∅)
Therefore, by the property of the superposition of waves, the amplitudes of linear waves are added linearly when they meet at the same point at a the same time
The given parameters for the wave are;
The time at which the value of the wave amplitude are given, t = 0.1025 seconds
The displacement of the sound wave A at the given time, "t" is A = 0.9739
The displacement of the sound wave B at the given time "t" is B = 0.6423
Therefore, the displacement of the sound A + B = 0.9739 + 0.6423 = 1.6162
