Answer:
The equation of the straight line is x - 2y +6 =0
Step-by-step explanation:
Explanation:-
Given a point ( 2, 4) and slope m = [tex]\frac{1}{2}[/tex]
The equation of the straight line passing through the point and having slope 'm'
y - y₁ = m ( x - x₁)
y - 4 = [tex]\frac{1}{2}[/tex] ( x - 2)
2( y -4) = ( x-2)
2 y - 8 = x -2
x - 2 y - 2 + 8 =0
x - 2y + 6 =0
The equation of the straight line is x - 2y +6 =0
