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ABC is a right angled triangle. All the measurements are in cm.
AB = x
BC = (x+2)
AC = (x+4)
Use the information to form a quadratic equation of the form x^2 + ax + b = 0, where a and b are constants which you need to find.

ABC is a right angled triangle All the measurements are in cm AB x BC x2 AC x4 Use the information to form a quadratic equation of the form x2 ax b 0 where a an class=

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ChoiSungHyun

Step-by-step explanation:

By Pythagoras' Theorem,

we have x² + (x + 2)² = (x + 4)².

=> 2x² + 4x + 4 = x² + 8x + 16

=> x² - 4x - 12 = 0

(The constants are a = -4, b = -12)

=> (x - 6)(x + 2) = 0

=> x = 6 or x = -2

The value x = -2 is rejected as side lengths cannot be negative.

Hence we have x = 6.

=> AB = 6cm, BC = 8cm, AC = 10cm.

P.S. What you see above is the full solution. You just need to type x² - 4x - 12 = 0 in the blank.

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