Step-by-step explanation:
y = mx + c, where m is the slope of the line and c is the y-intercept.
We have y = 3x - 4 as line L.
Slope of line L = 3
=> Slope of line L2 = -1/3
We have y = -1/3 x + c as our line L2 equation.
When x = 9, y = 5.
=> (5) = -1/3 * (9) + c
=> 5 = c - 3, c = 8
Hence the answer is y = -1/3 x + 8.
The equation of required line [tex]l_2[/tex] is .
Y = mX+c
[tex]Y = \frac{-1}{3} x + 2[/tex]
Given, The equation of straight line L.
Y=3X-4
compareing with the standard equation of line
Y=mX+c
slope of the equation of line L is [tex]m_1[/tex]= 3.
The product of slopes of two perpendicular lines is -1.
[tex]\rm m_1. m_2 = -1[/tex]
[tex]3.m_2 = -1\\m_2 = \frac{-1}{3}[/tex]
The slope of perpendicular line is and it passes through the point (9,5). So the equation of the line is
[tex]y = m_2x+c[/tex]
[tex]5 = -\frac{1}{3} . 9 + c[/tex]
5 = -3 + c
5+3 = c
c = 8
Therefore, the equation of required line [tex]l_2[/tex] is .
Y = mX+c
Y = [tex]\frac{-1}{3} X +8[/tex]
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https://brainly.com/question/24143133?
