Answer:
A. 2.2 ɥC
Explanation:
Given;
electric field strength, E = 1236 N/C
distance of the source charge, r = 4 m
Electric field strength is calculated as;
[tex]E = \frac{kQ}{r^2}[/tex]
where;
Q is the magnitude of the source charge
k is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]E = \frac{kQ}{r^2} \\\\kQ = Er^2\\\\Q = \frac{Er^2}{k} \\\\Q = \frac{(1236)(4^2)}{9 \ \times \ 10^9} \\\\Q = 2.197 \ \times \ 10^{-6} \ C\\\\Q = 2.197 \ \mu \ C[/tex]
Therefore, the correct option is A. 2.2 ɥC
