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24. The air in a small 250 cm birthday balloon is at a pressure of 760 torr. A boy sits on it at
party to pop it
decreasing the volume tc-220 cm just before it pops. What is the new pressure assuming
constant temperature.

Respuesta :

quasarJose

Answer:

1.14atm

Explanation:

Given parameters:

V1 = 250cm³ ;

              1000cm³ = 1dm³;  so this is 0.25dm³

P1  = 760torr

            760torr  = 1atm

       

V2  = 220cm³ ; 0.22dm³

Unknown:

New pressure = ?

Solution:

To solve this problem, we apply Boyle's law and we use the expression below:

       P1 V1 = P2V2

The unknown is P2;

            1 x 0.25  = P2 x 0.22

                 P2  = 1.14atm

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