Question 12
Given
The slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where m is the slope and b is the y-intercept
In our case:
substituting m = -1, and the point (-1, 5)
y = mx+b
5 = (-1)(-1) + b
5 = 1+b
b = 5-1
b = 4
Therefore, the value of y-intercept b = 4
now substituting m = -1 and b = 4 in the slope-intercept form of the line equation
y = mx+b
y = (-1)x + 4
y = -x+4
Thus, the slope-intercept of the line equation containing the point (-1, 5) and slope = -1 is:
y = -x+4
Question 13
Given
The slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where m is the slope and b is the y-intercept
In our case:
substituting m = 2, and the point (3, 3)
y = mx+b
3 = (2)(3) + b
3 = 6+b
b = 3-6
b = -3
Therefore, the value of y-intercept b = -3
now substituting m = 2 and b = -3 in the slope-intercept form of the line equation
y = mx+b
y = (2)x + (-3)
y = 2x-3
Thus, the slope-intercept of the line equation containing the point (3, 3) and slope = -3 is:
y = 2x-3
Therefore, option A is true.
