Answer:
v = 49.6 m/s
Explanation:
The vertical component of the final speed can be found by using 3rd equation of motion:
[tex]2gh = v_{y}^{2} - v_{0y}^{2}\\[/tex]
where,
g = acceleration due to gravity = 9.81 m/s²
h = height = 114 m
Voy = vetical component of initial velocity = 0 m/s (since the pelican is flying horizontally)
Vy = Vertical component of final velocity = ?
Therefore,
[tex](2)(9.81\ m/s^{2})(114\ m) = v_{y}^{2} - (0\ m/s)^{2}\\v_{y} = \sqrt{2236.68\ m^{2}/s^{2}}\\v_{y} = 47.3\ m/s[/tex]
Now, the horizontal component of the velocity is assumed to be the same because of negligible frictional force. Therefore,
Vx = 14.94 m/s
Thus the final speed will be given as:
[tex]v = \sqrt{v_{x}^{2} + v_{y}^{2}}\\\\v = \sqrt{(14.94\ m/s)^{2} + (47.3\ m/s)^{2}}\\\\[/tex]
v = 49.6 m/s
