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Pentagon WFNSC is shown on the coordinate grid. Pentagon WFNSC is dilated with the origin as the center of dilation using the rule (x, y)→(3x, 3y) to create pentagon pentagon W'F'N'S'C'. Which statement is true? Pentagon W'F'N'S'C' is larger than pentagon WFNSC because the scale factor is greater than 1. Pentagon W'F'N'S'C' is larger than pentagon WFNSC because the scale factor is less than 1. Pentagon W'F'N'S'C' is smaller than pentagon WFNSC because the scale factor is less than 1. Pentagon W'F'N'S'C' is smaller than pentagon WFNSC because the scale factor is greater than 1.

Pentagon WFNSC is shown on the coordinate grid Pentagon WFNSC is dilated with the origin as the center of dilation using the rule x y3x 3y to create pentagon pe class=

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Answer:b

Step-by-step explanation:

 Option A. Pentagon W'F'N'S'C' is larger than pentagon WFNSC because the scale factor is greater than 1.

Transformation of a figure by dilation:

  •  If a point (x, y) is dilated by a scale factor 'k', image point will be given by the rule,

          (x, y) → (kx, ky)

  •  If k > 1, image point will be larger than its preimage.
  •  If k < 1, image point will be smaller than its image.

Given in the question,

  • A pentagon WFNSC is dilated following the rule of dilation as,

        (x, y) → (3x, 3y)

Here, k > 3 which shows that the image will be larger than the preimage.

      Therefore, pentagon W'F'N'S'C' will be larger than pentagon WFNSC because the scale factor is greater than 1.

      Hence, Option A will be the answer.

Learn more about the transformation here,

https://brainly.com/question/19682392?referrer=searchResults

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