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20 points
A net force of 24 N is applied to an object for 5.0 s. The object is pushed a total of 5.2 m. What is the mass of the object? What equations will be used?

Respuesta :

Answer:

S = V0 t + 1/2 a t^2      net distance traveled

5.2 = a/2 * 25

a = 10.4 / 25 = ,416 m / s^2

F = m * a

m = F / a = 24 / .416 = 57.7 N

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