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PLEASE HELP ME!!!! WILL GIVE BRAINLIEST!!!!

1. What is the molality of a solution made up of 43.6 mol of CaCl2 dissolved by 13.5 kg of water?

2. How many moles of Na2CO3 are required to create 9.54 liters of a 3.4 M solution?

3. Which of these actions can result in decreasing the molarity of a solution?

Select all that apply.

A

adding solute

B

adding solvent

C

removing solute

D

removing solvent

Thanks Y'all:)

Respuesta :

Answer: 1. 3.23 m

2. 32.4

3. B  adding solvent  and C  removing solute

Explanation:

1. Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent

[tex]Molality=\frac{n}{W_s}[/tex]

where,

n = moles of solute

[tex]W_s[/tex] = weight of solvent

Now put all the given values in the formula of molality, we get

[tex]Molality=\frac{43.6mol}{13.5kg}=3.23mol/kg[/tex]

2. Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in L

[tex]3.4=\frac{n}{9.54}[/tex]

[tex]n=32.4[/tex]

Therefore, the moles of [tex]Na_2CO_3[/tex] is 32.4

3. Molarity can be decreased by decreasing the moles of solute and by increasing the volume of solution.

Thus adding solvent  and removing solute will decrease the molarity.

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