eniolaendurance0501
eniolaendurance0501
17-01-2021
Mathematics
contestada
Multiply (3+b) × (4+2b)
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cuviulvliy
cuviulvliy
17-01-2021
(3+b)*(4+2b)=3*4+3*2b+b*4+b*2b=
=12+6b+4b+2b^2=12+10b+2b^2=2(6+5b+b^2)=
=2(b^2+5b+6)
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