Answer/Step-by-step explanation:
First, find the slope (m) of Line L using the points (0, 5) and (2, 1):
[tex] slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 5}{2 - 0} = \frac{-4}{2} = -2 [/tex]
Slope (m) = -2
✔️Since the line is parallel bro Line L, it would also have the same slope value of -2.
We can use the slope (m) and a point (a, b) of the line to find its equation using the point-slope formula, y - b = m(x - a).
Substitute (a, b) = (3, 0), and m = -2 into y - b = m(x + a):
Thus,
✅y - 0 = -2(x + 3)
Rewrite equation in slope-intercept form
y = -2(x + 3)
✅y = -2x - 6
