Given :
A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 m
this wrecking ball is released from an angle of 40 degrees.
To Find :
The height from the lowest point of the arc.
Solution :
From the attached image we have to find the value of h.
So,
[tex]cos \ 40^o = \dfrac{L-h}{L}\\\\0.76=\dfrac{25-h}{25}\\\\h = 25( 1- 0.76)\\\\h = 6 \ m[/tex]
Hence, this is the required solution.
