Answer:
Part A)
The equation in the point-slope form is:
[tex]y-11=\frac{4}{3}\left(x-\left(-2\right)\right)[/tex]
Part B)
The graph of the equation is attached below.
Step-by-step explanation:
Part A)
Given
The point-slope form of the line equation is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
Here, m is the slope and (x₁, y₁) is the point
substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-11=\frac{4}{3}\left(x-\left(-2\right)\right)[/tex]
Thus, the equation in the point-slope form is:
[tex]y-11=\frac{4}{3}\left(x-\left(-2\right)\right)[/tex]
Part B)
As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3
The graph of the equation is attached below.
