For this case we have:
By definition, one of the properties of the power, known as negative integer power, states that:
[tex]a ^{-b}[/tex]can be written as[tex]\frac{1}{a ^ b}[/tex]
Thus, [tex]7 ^{-2}[/tex] can be written as [tex]\frac{1}{7 ^ 2}[/tex] . So:
[tex]\frac{1}{7 ^ 2}= \frac{1}{(7 * 7)}=\frac{1}{49}[/tex]
Answer:
Power of negative integer exponent:
[tex]7^{-2} =\frac{1}{7 ^ 2}= \frac{1}{(7 * 7)}=\frac{1}{49}[/tex]
