The molarity of the solution : 1.2 M
Further explanation
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
mass of NaCl=35 g
Volume of solution = 0.5 L
mol NaCl(MW=58.44 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{35}{58.44}\\\\mol=0.6[/tex]
The molarity :
[tex]\tt M=\dfrac{0.6}{0.5}=1.2[/tex]
