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Elijah throws a tennis ball vertically upward. The ball returns to the point of release after 3.5 s. What is the speed of the ball as it is released?

Respuesta :

Loliypop3
t(return)=3.5 s 

h = vt - (1/2)gt^2 

to the point of release or return h=0 
vt - (1/2)gt^2=0 
t(v - gt/2)=0 ==> 
t(release)=0 or v - (1/2)gt(return)=0 ==> 
v = (1/2)gt(return) 
v=9.81*3.5/2 
v=17.17 m/s

Hope i helped! :)

The speed of the ball as it is released is 17.15 m/s.

  • The calculation is as follows:

The acceleration should be 9.8

The time taken should be 3.5 seconds

Now the speed is

[tex]= 9.8 \times 3.5[/tex]

= 17.15 m/s

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