Respuesta :

calculista

we know that

When a product of two or more terms equals zero, then at least one of the terms must be zero

we have

[tex](x-6)(x+8)=0[/tex]

We shall solve each term separately

First solution

[tex](x-6)=0[/tex]

Adds [tex]6[/tex] both sides

[tex](x-6)+6=0+6[/tex]

[tex]x=6[/tex]

Second solution

[tex](x+8)=0[/tex]

Subtract [tex]8[/tex] both sides

[tex](x+8)-8=0-8[/tex]

[tex]x=-8[/tex]

therefore

the answer is

The solutions are

[tex]x=6[/tex]

[tex]x=-8[/tex]

Answer:

The solution of the equation [tex](x -6)(x + 8) = 0[/tex] is 6 and -8.

Step-by-step explanation:

Given :  The equation [tex](x-6)(x + 8) = 0[/tex]

We have to find the solution to the given equation [tex](x -6)(x + 8) = 0[/tex]

Consider the given equation [tex](x -6)(x + 8) = 0[/tex]

Apply zero product rule, [tex]a\cdot b=0 \Rightarrow a=0 \ or \ b=0[/tex]

Thus, [tex](x -6)(x + 8) = 0[/tex] gives,

[tex](x -6)=0[/tex] and [tex](x + 8) = 0[/tex]

Simplify, we have,

[tex]x=6[/tex] and [tex]x=-8[/tex]

Thus, The solution of the equation [tex](x -6)(x + 8) = 0[/tex] is 6 and -8.

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