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What would happen to a cell if its cytoplasm contains 97% water and 3% solute and it is placed into a container that has a solution of 92% water and 8% solute?

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The cell would probably get smaller

A cell if its cytoplasm contains 97% water and 3% solute and it is placed into a container that has a solution of 92% water and 8% solute - cell will lose water and shrink.

A hypertonic solution, the solution has a lower water concentration than the cell cytosol, and water moves out of the cell until both solutions are isotonic

  • if you place a cell in a hypertonic solution, the cell shrinks
  • it loses water as due to osmosis water moves from a higher concentration inside the cell to a lower concentration outside
  • The water will move out of the cell to try to equalize.

Thus, A cell if its cytoplasm contains 97% water and 3% solute and it is placed into a container that has a solution of 92% water and 8% solute - cell will lose water and shrink.

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