Simple....
you have: [tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]
To solve for x:
[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]
1.) Isolate the variable "x" (Remove y)
[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]
[tex]- \frac{5}{6} y[/tex] [tex]- \frac{5}{6} y[/tex]
Leaving you with....
[tex] \frac{3}{4} x=-\frac{5}{6}y +15[/tex]
2.) Divide by the variable.....
[tex] \frac{ \frac{3}{4}x }{ \frac{3}{4} } = \frac{ -\frac{5}{6}y+15 }{ \frac{3}{4} } [/tex]
Leaving you with...
x=[tex] -\frac{10y}{9} +20[/tex]
Now, solve for y.
To solve for y:
[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]
1.)Isolate the variable "y" (Remove x)
[tex]- \frac{3}{4} x+ \frac{5}{6} y=15[/tex]
[tex]+ \frac{3}{4} [/tex] [tex]+ \frac{3}{4} [/tex]
Leaving you with....
[tex] \frac{5}{6} y= \frac{3}{4} x+15[/tex]
2.)Divide by the variable.....
[tex] \frac{ \frac{5}{6}y }{ \frac{5}{6} } = \frac{ \frac{3}{4}x+15 }{ \frac{5}{6} } [/tex]
Leaving you with....
y=[tex] \frac{9x}{10} +18[/tex]
x-intercept: (-20,0)
y-intercept: (0,18)
Thus, your answer.
