Respuesta :
A×4 = E, so A = E/4
B/4 = E, so B = 4E
C+4 = E, so C = E=4
D-4 = E, so D = E+4
and
A+B+C+D=100.
now substitute the values that we got of A, B, C and D in the equation, to get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
E = 16
i answered same question before too ....
Hope it helps !!!
B/4 = E, so B = 4E
C+4 = E, so C = E=4
D-4 = E, so D = E+4
and
A+B+C+D=100.
now substitute the values that we got of A, B, C and D in the equation, to get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
E = 16
i answered same question before too ....
Hope it helps !!!
we know that
[tex] A*4=E [/tex]
[tex] A=\frac{E}{4} [/tex] -----> equation [tex] 1 [/tex]
[tex] \frac{B}{4} =E\\ \\ B=4*E [/tex] -----> equation [tex] 2 [/tex]
[tex] C+4=E [/tex]
[tex] C=E-4 [/tex] -----> equation [tex] 3 [/tex]
[tex] D-4=E [/tex]
[tex] D=E+4 [/tex] -----> equation [tex] 4 [/tex]
[tex] A+B+C+D=100 [/tex] -----> equation [tex] 5 [/tex]
Substitute equations [tex] 1,2,3,4 [/tex] in equation [tex] 5 [/tex]
[tex] [\frac{E}{4} ]+[4*E]+[E-4]+[E+4]=100\\ E+16E+4E-16+4E+16=400\\ 25E=400\\\\ E=\frac{400}{25} \\ \\ E=16 [/tex]
therefore
the answer is
the value of E is [tex] 16 [/tex]