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What is the center and radius of the circle with the equation x2 + y2 + 8x – 12y + 36 = 0 ?. Center: (5, 6); Radius = 4. Center: (–4, 6); Radius = 5. Center: (5, 6); Radius = 5. Center: (–4, 6); Radius = 4.

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The best and most correct answer among the choices provided by your question is the fourth choice which is "Center: (–4, 6); Radius = 4."

(x² + 8x) + (y² - 12y) = - 36 

(x² + 8x + 16) + (y² - 12y + 36) = - 36 + 16 + 16 

(x + 4)² + (y - 6)² = 16 

C (- 4 , 6 ) , r = 4

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Acuteprettygirl

Answer: Center:(-4,6)

Radius:4

Step-by-step explanation:

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