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If PEs represents the potential energy stored in a spring at kg times m/s sqaured, and x represents the change in spring length from its equilbrium position in m, what is the unit for the spring constant k in the formula PEs=1/2kx squared?

Respuesta :

 PE = 1/2 . k . x^2 = kg . m^2 / s^2 

Forget the 1/2 , it has no units 

k = kg . m^2 / s^2 / m^2 = kg / s^2 

Therefore, the unit of the spring constant k would be  kg / s^2.

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