For the simple harmonic motion equation d=9cos((pi/2)t), what is the period?
A cosine function y = a cos bt + d has a period of (in terms of radians) P = 2π/b, where here the "b" value is π/2..thus plug π/2 for b in the period formula and evaluate..
2π/(π/2) <-- flip second fraction and multiply..
= 2π * 2/π <-- the π's cancel out..leaving us with just..
= 4 <-- answer...
Thus, the period is 4.
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