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Estimate the heat of neutralization of H3PO4 in kJ/mol given these data:

Heat transferred = 2.4 x 102 J

Moles of H3PO4 = 1.5 x 10−3 mol

Moles of NaOH = 5.0 x 10−3 mol

Respuesta :

Thank you for posting your question here. I hope the answer helps. Moles of water formed = 4.5 * 10^-3 mole since H+ + OH- = H2O and H+ is the limiting reactant. 

230 J / 4.5 * 10^-3 mole = 51.1 kJ/mole

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