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Plzzzz help ASAP. What is an equation of the line that passes through the point (1,6) and is perpendicular to the line x+3y=27

Plzzzz help ASAP What is an equation of the line that passes through the point 16 and is perpendicular to the line x3y27 class=

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devishri1977

Answer:

   y = 3x + 3

Step-by-step explanation:

x + 3y = 27

     3y = -x + 27

      y = [tex]\frac{-1}{3}x +\frac{27}{3}[/tex]

      y = [tex]\frac{-1}{3}x + 9[/tex]

m₁ = -1/3

the slope of the line perpendicular to x + 3y = 27 is m₂ = -1/m₁

    m₂ = [tex]-1 * \frac{-3}{1}[/tex] = 3 ,  Point (1 , 6)

y - y1 = m (x -x1)

y -6 = 3(x - 1)

y - 6= 3x - 3

    y = 3x - 3 +6

   y = 3x + 3

Answer:

3x-y=27

Step-by-step explanation:

perpendicular is making a 90 degree angle, so it would need to be a slope of 3 if the other is -1/3.

y=9, x=27

3x-y=27 is the polar opposite, and should work, sorry if wrong. hard to do in my head without a graph to help.

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