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Find a center of mass of a thin plate of density delta equals 5δ=5 bounded by the lines y equals xy=x and x equals 0x=0 and the parabola y equals 20 minus x squaredy=20−x2 in the first quadran

Respuesta :

batolisis

Answer:

center of mass

X = [tex]\frac{my}{m} = \frac{28}{19}[/tex]

Y = [tex]\frac{mx}{m} = \frac{872}{95}[/tex]

Step-by-step explanation:

y = x and x = 0

parabola ; y = 20 - x^2

attached below is the detailed solution

M = [tex]\frac{152}{3}[/tex]б

Mx =  [tex]\frac{6976}{15}[/tex]б

My = [tex]\frac{224}{3}[/tex]б

X = [tex]\frac{my}{m} = \frac{28}{19}[/tex]

Y = [tex]\frac{mx}{m} = \frac{872}{95}[/tex]

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