PLZ HURRY!!!
What is the equation of the line in slope-intercept form?

Line on a coordinate plane. The line runs through points begin ordered pair negative 5 comma 0 end ordered pair and begin ordered pair 0 comma 3 end ordered pair.

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y =
x +

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Answer:

y =  [tex]-\frac{3}{5}[/tex] x + 3

Step-by-step explanation:

To find slope you need to take y2-y1 divided by x2-x1. First to the subtraction. Y2 is 3 in this problem and y1 is 0. X2 is 0 and x1 is 5. 3-0 = 3 and 0-5 = -5. Now we have the equation [tex]-\frac{3}{5}[/tex] as the slope.

Slope-intercept form is y= mx+b so plug in  [tex]-\frac{3}{5}[/tex]  to get y =  [tex]-\frac{3}{5}[/tex] x + b

The y-intercept is the coordinate where the x is equal to zero. (0,3) is the coordinate that meets this requirement. The y coordinate is 3 so that is the y-intercept. Plug that in to y =  [tex]-\frac{3}{5}[/tex] x + b to get =  [tex]-\frac{3}{5}[/tex] x + 3.

The other person was parcially correct, but here is the right answer:

Ver imagen noelmusulin1