pythagorean theorem level two deltamath. help asap!!

Answer:
65
Step-by-step explanation:
Just use the Pythagorean theorem.
[tex]\boxed{a^2+b^2=c^2}[/tex]
[tex]33^2 + 56^2 = c^2\\1089 + 3136 = c^2\\4225 = c^2\\c = \sqrt{4225} \\c= 65[/tex]
Answer:
Third side is 65
Step-by-step explanation:
FORMULA
a^2 + b^2 = c^2
PLUG IT IN
33^2 + 56^2 = c^2
33 and 56 are the legs of the triangle so they go into the A and B variable.
The legs make up the right angle.
C is the hypotenuse, and here it is the diagonal line in that image.
FIND THE NUMBERS SQUARED
1089 + 3136 = c^2
ADD THEM TOGETHER
4225 = c^2
SQUARE ROOT BOTH SIDES
[tex]\sqrt{4225}[/tex] = ([tex]\sqrt{C}[/tex])^2
65 = c
CHECK
33^2 + 56^2=65^2
1089 + 3136 = 4225
4225 = 4225