Answer:
Solving the equation [tex]x^2+6x-8=0[/tex] by completing the square method we get [tex]\mathbf{(x+3)^2=17}[/tex]
Option B is correct option.
Step-by-step explanation:
We need to solve the equation [tex]x^2+6x-8=0[/tex] by completing the square method.
For completing the square method: we need to follow: [tex]a^2+2ab+b^2=(a+b)^2[/tex]
We are given:
[tex]x^2+6x-8=0[/tex]
Solving by completing the square
[tex]x^2+2(x)(?)+(?)^2-8=0[/tex]
We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.
So, adding and subtracting (3)^2
[tex]x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17[/tex]
So, solving the equation [tex]x^2+6x-8=0[/tex] by completing the square method we get [tex]\mathbf{(x+3)^2=17}[/tex]
Option B is correct option.
