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A rock is thrown horizontally off of a cliff with a velocity of 20 m/s. The rock lands 60 m from the base of the cliff. How long will the rock be in the air?

Respuesta :

onyebuchinnaji

Answer:

The time spent by the rock in air is 3 s.

Explanation:

Given;

initial  horizontal velocity of the rock, u = 20 m/s

horizontal distance traveled by rock, R = 60 m

The the range of the projectile is given by;

R = vt

where;

v is the initial  horizontal velocity of the rock

t is the time spent by the rock in air

t = R/v

t = 60 / 20

t = 3 s

Therefore, the time spent by the rock in air is 3 s.

Cricetus

The time spend by the rock will be "3 s".

Given values are:

Initial horizontal velocity,

  • u = 20 m/s

Horizontal velocity,

  • R = 50 m

The range of projectile will be:

→ [tex]R = vt[/tex]

or,

→ [tex]t = \frac{R}{v}[/tex]

By substituting the values,

     [tex]= \frac{60}{20}[/tex]

     [tex]= 3 \ s[/tex]

Thus the response above is right.

Learn more about velocity here:

https://brainly.com/question/21717010

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