Complete Question
The complete question is shown on the first uploaded image
Answer:
The components of reaction at the fixed support are
[tex]A_{(x)} = 400 \ N[/tex] , [tex]A_{(y)} = -500 \ N[/tex] , [tex]A_{(z)} = 600 \ N[/tex] , [tex]M_x = 1225 \ N\cdot m[/tex] , [tex]M_y = 750 \ N\cdot m[/tex] , [tex]M_z = 0 \ N\cdot m[/tex]
Explanation:
Looking at the diagram uploaded we see that there are two forces acting along the x-axis on the fixed support
These force are 400 N and [tex]A_{(x)}[/tex] [ i.e the reactive force of 400 N ]
Hence the sum of forces along the x axis is mathematically represented as
[tex]A_{(x)} - 400 = 0[/tex]
=> [tex]A_{(x)} = 400 \ N[/tex]
Looking at the diagram uploaded we see that there are two forces acting along the y-axis on the fixed support
These force are 500 N and [tex]A_{(y)}[/tex] [ i.e the force acting along the same direction with 500 N ]
Hence the sum of forces along the x axis is mathematically represented as
[tex]A_{(y)} + 500 = 0[/tex]
=> [tex]A_{(y)} = -500 \ N[/tex]
Looking at the diagram uploaded we see that there are two forces acting along the z-axis on the fixed support
These force are 600 N and [tex]A_{(z)}[/tex] [ i.e the reactive force of 600 N ]
Hence the sum of forces along the x axis is mathematically represented as
[tex]A_{(z)} - 600 = 0[/tex]
=> [tex]A_{(z)} = 600 \ N[/tex]
Generally taking moment about A along the x-axis we have that
[tex]\sum M_x = M_x - 500 (0.75 + 0.5) + 600 ( 1 ) = 0[/tex]
=> [tex]M_x = 1225 \ N\cdot m[/tex]
Generally taking moment about A along the y-axis we have that
[tex]\sum M_y = M_y - 400 (0.75 ) + 600 ( 0.75 ) = 0[/tex]
=> [tex]M_y = 750 \ N\cdot m[/tex]
Generally taking moment about A along the z-axis we have that
[tex]\sum M_z = M_z = 0[/tex]
=> [tex]M_z = 0 \ N\cdot m[/tex]
