Answer:
300lb-ft/secs
Explanation:
Given parameters:
Weight of Peter = 100lb
Height of hill = 6ft
Time taken = 2s
Unknown:
Power output of Peter = ?
Solution:
Power is the rate at which work is being done. It is expressed as;
Power = [tex]\frac{Work done }{time taken}[/tex]
Work done = force x distance = weight x height = 100lb x 6ft
Work done = 600lb-ft
Power = [tex]\frac{600}{2}[/tex] = 300lb-ft/secs
