The car's rate of centripetal acceleration in the circular path is 4.8 m/s².
The given parameters;
- mass of the car, m = 2,000 kg
- velocity of the car, v = 12 m/s
- radius of the circular path, r = 30 m
The centripetal acceleration of the car is calculated as follows;
[tex]a_c = \frac{v^2}{r}[/tex]
where;
- v is the tangential speed of the car
- r is the radius of the circular path
Substitute the given parameters and solve for the centripetal acceleration;
[tex]a_c = \frac{12^2}{30} \\\\a_c = 4.8 \ m/s^2[/tex]
Thus, the car's rate of centripetal acceleration is 4.8 m/s².
Learn more here:https://brainly.com/question/11700262
