If it takes 820 Joules of heat to warm a sample of zinc from 0°C to 50°C, what would be the mass of the zinc? Note: Zinc has a specific heat of 380 J/kg °C.

Respuesta :

Answer:

m = 43.1 g

Explanation:

Given that,

Heat to warm the sample, Q = 820 J

Initial temperature = 0°C

Final temperature = 50°C

The specific heat of zinc is, c = 380 J/kg °C

We need to find the mass of the zinc. The specific heat in terms of mass and temperature is calculated by the relation as follows :

[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\=\dfrac{820}{380\times (50-0)}\\\\=0.0431\ kg\\\\=43.1\ g[/tex]

So, the mass of the sample is 43.1 g.

Answer:

43.1 g

Explanation: