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To exercise, a man attaches a 4.0 kg weight to the heel of his foot. When his leg is stretched out before him, what is the torque exerted by the weight about his knee, 40 cm away from the weight? Use g = 10 m/s2. A. 160 Nâm B. 16 Nâm C. 1600 Nâm D. 1.6 Nâm

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hamzaahmeds

Answer:

B. τ = 16 Nm

Explanation:

In order to find the torque exerted by the weight attached to the heel of man's foot, when his leg is stretched out. We use following formula:

τ = Fd

here,

τ = Torque = ?

F = Force exerted by the weight = Weight = mg

F = mg = (4 kg)(10 m/s²) = 40 N

d = distance from knee to weight = 40 cm = 0.4 m

Therefore,

τ = (40 N)(0.4 m)

B. τ = 16 Nm

Lanuel

The torque exerted by the weight about his knee, 40 cm away from the weight is: D. 1.6 Nm

Given the following data:

  • Mass = 4.0 kg
  • Distance = 40 cm to m = 0.04 meters
  • Acceleration due to gravity (g) = 10 [tex]m/s^2[/tex].

To determine the torque exerted by the weight about his knee, 40 cm away from the weight:

First of all, we would calculate the force being exerted by the weight on his heel.

[tex]Force = mg\\\\Force = 4 \times 10[/tex]

Force = 40 Newton

Mathematically, torque is given by the formula:

[tex]Torque = force \times distance[/tex]

Substituting the given parameters into the formula, we have;

[tex]Torque = 40 \times 0.04[/tex]

Torque = 1.6 Nm

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