Mol of Kr gas = 1.244
Further explanation
In general, the gas equation can be written
PV=nRT
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08205 L.atm / mol K
T = temperature, Kelvin
P=1.31 atm
V=23.3 L
T=26+273=299 K
mol of sample :
[tex]\tt n=\dfrac{PV}{RT}=\dfrac{1.31\times 23.3}{0.08205\times 299}=1.244[/tex]
