Answer:
The correct solution will be "12.0 A".
Explanation:
The given values are:
[tex]N_p= 500 \ turn[/tex]
[tex]N_s= 200 \ turn[/tex]
[tex]I_s= 3.0 \ A[/tex]
By using the transformer formula, we get
⇒ [tex]\frac{N_p}{N_s} =\frac{I_s}{I_p}[/tex]
⇒ [tex]I_p = I_s\times \frac{N_s}{N_p}[/tex]
On substituting the given values, we get
⇒ [tex]=3.0 \ A\times \frac{2000}{500}[/tex]
⇒ [tex]=12.0 \ A[/tex]
