Answer:
120 mL of 10% HCL will be used.
Step-by-step explanation:
to solve this, we have to generate an equation for the mixture, to get the volume of 10% HCl needed.
Let the volume needed = x
5% of x + (20% of 60ml) = 10% of ( 60 + x) ml of new mixture
0.05x + (0.2 × 60) = 0.1 × (60 + x)
0.05x + 12 = 6 + 0.1x
12 - 6 = 0.1x - 0.05x
6 = 0.05x
x = 6 ÷ 0.05
x = 120
Therefore, 120 mL of 10% HCL will be used.
